Question

How many degenerate orbitals are present in a subshell if the electron associated with it has an orbital angular momentum $=\frac{2\sqrt{3}h}{2\pi }$

• A. No degenerate orbitals
• B. Seven degenerate orbitals
• C. Three degenerate orbitals
• D. The number of degenerate orbitals is same as the subshell which has orbital magnetic moment ${\mu }_L=3.46\text{BM}$

Answer 1

Answer: (B), (D)

The number of degenerate orbitals is same as the subshell which has orbital magnetic moment ${\mu }_L=3.46\text{BM}$

Orbital angulat momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }=\frac{2\sqrt{3}h}{2\pi }$
$\Rightarrow l^2+l-12=0$
$\Rightarrow l=3or-4$
$l=3$, represents the $f$ subshell which has seven degenerate orbitals.