How many degree of unsaturation are there in a molecule of- N - C-CH2-CH2-CO-NH-CH-CH2-

The correct option is A 4 #160; N ≡ C CH_2 CH_2 O||C NH CH=CH_2 #160; #160;Degree of unsaturation due to double bond = 1Degree of unsaturation due to ...

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Standard X

Chemistry

Saturated and Unsaturated Hydrocarbons

How many degr...

Question

How many degree of unsaturation are there in a molecule of: $N \equiv C - C H_{2} - C H_{2} - C O - N H - C H = C H_{2}$ ?

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Solution

The correct option is A 4
$N \equiv C - C H_{2} - C H_{2} - C | | O - N H - C H = C H_{2}$
Degree of unsaturation due to double bond = 1
Degree of unsaturation due to triple bond = 2
There are two double bonds and one triple bond.
So total degree of unsaturation = 4

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Similar questions

Q. How many sigma and pi bonds are there in the given molecule?

H - C \equiv C - C H_{2} - C H = C H_{2}

Q. How many

σ

and

π

bonds are there in

{C H}_{2} = C H - C \equiv C H

Q. Which of the following lone-pair indicated is not involved in resonance?
(A)

C H_{2} = C H - . . N H - C H_{3}

(B)

C H_{2} = C H - . . O . . - C H_{3}

(C)

C H_{2} = C H - . . O . . - C H = C H_{2}

(D)

C H_{2} = C H - N H_{2}

Q. How many sigma and pi bonds are present in the molecule given below:

C H_{2} = C = C H - C H_{3}

Q. How many monochlorinated products are possible including stereoisomers?

C H_{3} - C H_{2} - C H = C H_{2} C l_{2} - - \to h ν

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How many degree of unsaturation are there in a molecule of: N≡C−CH2−CH2−CO−NH−CH=CH2?

The correct option is A 4N≡C−CH2−CH2−C||O−NH−CH=CH2 Degree of unsaturation due to double bond = 1Degree of unsaturation due to triple bond = 2There are two double bonds and one triple bond.So total degree of unsaturation = 4

How many degree of unsaturation are there in a molecule of: $N \equiv C - C H_{2} - C H_{2} - C O - N H - C H = C H_{2}$ ?

The correct option is A 4
$N \equiv C - C H_{2} - C H_{2} - C | | O - N H - C H = C H_{2}$
Degree of unsaturation due to double bond = 1
Degree of unsaturation due to triple bond = 2
There are two double bonds and one triple bond.
So total degree of unsaturation = 4