Question

How many degrees of freedom are associated with 2grams of He at NTP?

• A. 3
• B. $3.01\times {10}^{23}$
• C. $9.03\times {10}^{23}$
• D. 6

Answer 1

The correct option is C $9.03\times {10}^{23}$

Moles of He =$\frac{2}{4}$ = $\frac{1}{2}$
Molecules = $\frac{1}{2}\times 6.02\times {10}^{23}$ = $3.01\times {10}^{23}$
As there are 3 degrees of freedom corresponding of 1 molecule of a monatomic gas.
$\therefore$ Total degrees of freedom = $3\times 3.01\times {10}^{23}$
$=9.03\times {10}^{23}$