Question

How many diagonals are there in a Pentagon

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Number}\mathrm{of}\mathrm{diagonals}\mathrm{in}\mathrm{polygon}\mathrm{having}\mathrm{n}\mathrm{sides}=\frac{\mathrm{n}\left(\mathrm{n}-3\right)}{2} \\ \mathrm{For}\mathrm{pentagon},\mathrm{n}=5 \\ \mathrm{Number}\mathrm{of}\mathrm{diagonals}\mathrm{in}\mathrm{pentagon}=\frac{5\left(5-3\right)}{2} \\ =\frac{5\times 2}{2}=5\mathrm{ANS}... \end{gathered}$$

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