Question

How many diastereomers are possible for the given compound?

Answer 1

A total of $2^n$ steroisomers are possible for a compound where, n = number of stereocenters or chiral centers. So, here we have n = 3.
$\therefore$ $2^3=8$ stereoisomers are possible out of which, two of the isomers are a pair of enantiomer and rest six are diastereomers.