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Question

How many different 4-digit numbers are possible to construct using the digits 1,3,4,6,7,8 that satisfy all these conditions.
1. the number is between 3300 and 7200
2. the number is even
3. the number has no repeated digit.

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Solution

Odd digits 1,3,7. Even digits 4,6,8
1st place can be filled by 3,4,6,7

Case I: 3 is at 1st place.
3
Since number is even, 4th place can be filled in 3 ways and 2nd place in 3 ways.
Number of ways =1×3×3×3=27

Case II: 4 is at 1st place.
4
Number of ways =1×4×3×2=24

Case III: 6 is at 1st place.
6
Number of ways =1×4×3×2=24

Case IV: 7 is at 1st place.
7
Number of ways =1×1×3×3=9

Hence, total number of ways
=27+24+24+9=84 ways

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