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Question

How many different Arithmetic Progressions can you form with atleast three terms with first term 2 and last term 999?

A
1
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B
3
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C
5
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D
6
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E
none of these
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Solution

The correct option is A 1

Option e

The number of AP’s = (Number of factors of 997 - 1), which is prime.
Hence only one AP’s of 998 terms can be formed.
Answer is option a


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