Question

How many different arrangements can be made out of the letters in the expression $a^3{b}^2{c}^4$ when written at full length?

• A. $1240$
• B. $1250$
• C. $1260$
• D. $1270$

Answer 1

Answer: (C)

$1260$

Given, $a^3,b^2,c^4$

$3a^{1}s,2b^{1}s,4c^{1}s$ Total =9 letters

Total no. of arrangements $=\frac{9!}{3!2!4!}=1260$