Question

How many different arrangements can be made out of the letters in the expression $a^3{b}^2{c}^4$ when written at full length?

Answer 1

Total no. of letters $=9$
Number of $a^{\prime }s=3$
Number of $b^{\prime }s=2$
Number of $c^{\prime }s=4$
$\therefore$ Total number of arrangements $=\frac{9!}{3!2!4!}$
$=1260$