How many different chlorides in total could be prepared by the reaction of dilute hydrochloric acid with the following substances?
Copper, Magnesium, Silver, Zinc carbonate

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Solution

The correct option is C 2
Copper and silver do not react with dilute $H C l$ as they come down in activity series so they are unreactive to mineral acids while magnesium reacts to give magnesium chloride and zinc carbonate with $H C l$ gives zinc chloride so there are two types of chlorides formed with the given compounds.

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Q. Dilute hydrochloric acid reacts with zinc to evolve _____ gas along with the formation of zinc chloride salt.

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How many different chlorides in total could be prepared by the reaction of dilute hydrochloric acid with the following substances?Copper, Magnesium, Silver, Zinc carbonate

How many different chlorides in total could be prepared by the reaction of dilute hydrochloric acid with the following substances?
Copper, Magnesium, Silver, Zinc carbonate