How many different kinds of gametes will be produced by a plant having genotype AaBBCcDd?

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Solution

The correct option is B 8
Gametes $\to$ ABcD
ABCd
ABcD
ABcd
aBCD
aBCd
aBcD
aBcd

Formula for the number of gametes
= $2^{n}$
where n = number of heterozygous allele pairs which in this case is 3
therefore, $2^{3}$ = 8.

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How many different types of genetically different gametes will be produced by a heterozygous plant having the genotype AaBbCc?

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