How many different numbers can be formed by using six out of the nine digits $1, 2, 3, . . . . .9$ ?

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Solution

Here we have $9$ different things and we have to find the number of permutations of them taken $6$ at a time.
$∴$ the required result is $=$ $^{9} P_{6}$
$= 9 \times 8 \times 7 \times 6 \times 5 \times 4$
$= 60480$ .

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How many different numbers can be formed by using six out of the nine digits 1,2,3,.....9?

Here we have 9 different things and we have to find the number of permutations of them taken 6 at a time.∴ the required result is = 9P6=9×8×7×6×5×4=60480.

How many different numbers can be formed by using six out of the nine digits $1, 2, 3, . . . . .9$ ?

Here we have $9$ different things and we have to find the number of permutations of them taken $6$ at a time.
$∴$ the required result is $=$ $^{9} P_{6}$
$= 9 \times 8 \times 7 \times 6 \times 5 \times 4$
$= 60480$ .