CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many different numbers of 2-digits can be formed with the digits 1, 2, 3, 4, 5, 6; no digits being repeated?

A
40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
35
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
45
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 30
We have to fill up two places (since numbers are of 2 digits.
The first place can be filled up in 6 ways. as any 1 of the 6 digits can be placed in the first place. The 2nd place can be filled up in 5 ways as no digit is to be repeated. Hence, both places can be filled up in 6×5=30 ways.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Consecutive Numbers
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon