Question

How many different numbers of seven digits divisible by $10$ can be formed by using the digits $1,2,0,1,2,2,5$ without repeatition?

Answer 1

So, $\frac{6!}{3!2!}$

$=\frac{4\times 5\times 6}{2}$

$=60$ways.

Hence, the answer is $60$ways.