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Question
How many different possible alkenes are formed when 2-chlorobutane is treated with ethanolic solution of KOH?
How many different possible alkenes are formed when 2-chlorobutane is treated with ethanolic solution of KOH?
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Solution
The correct option is C 3
Dehydrohalogenation involves removal of (elimination of) a hydrogen halide by abstracting β−H from a alkyl halide in presence of base (alc. KOH) to form alkenes.
Saytzeff product will be major product.
here one of the product is but-2-ene and it can exist as cis and trans form thus two different alkenes will be formed.
Hence total possible alkene that can be formed is three.
Dehydrohalogenation involves removal of (elimination of) a hydrogen halide by abstracting β−H from a alkyl halide in presence of base (alc. KOH) to form alkenes.
Saytzeff product will be major product.
here one of the product is but-2-ene and it can exist as cis and trans form thus two different alkenes will be formed.
Hence total possible alkene that can be formed is three.
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