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Question

How many different products can be obtained by multiplying two or more of the numbers 3,5,7,11 (without repetition)?


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Solution

It is clear that product is obtained by multiplying atleast two of the given four numbers (without repetition)

The required number of ways of getting different products are:

4C2+ 4C3+ 4C4

=6+4+1

=11

Hence the number of ways of getting different products is 11


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