Question

How many different types of gametes can be formed by $F_1$ progeny, resulting from the following cross:
AA BB CC $\times$ aa bb cc.

• A. 3
• B. 8
• C. 27
• D. 64

Answer 1

The correct option is B 8

• The F${}_1$ generation formed by the cross between

• AA BB CC x aa bb cc is Aa Bb Cc.

• Here, there are three different types of genes involved. The maximum number of gametes possible is given by 2${}^n$.

• In the given case, n = 3. Therefore the maximum number of combinations = 2${}^n$ = 8.

• The possible combinations: ABC, ABc, AbC, Abc, aBC, aBc, abC and abc.
  Hence, option b is correct.