The correct option is C n(n−1)2
From the nth state, the atom may go to (n – 1)th state, …., 2nd state or 1st state. So there are (n– 1) possible transitions starting from the nth state. The atom that reached (n – 1)th state may make (n – 2) different transitions to reach 1st state. Similarly for the one reaching at (n-2), it will take (n – 3) different transitions. Similarly for other lower states. The total number of possible transitions is
(n – 1) + (n – 2) + (n – 3) + …. 2 + 1
=n(n−1)2
Just simple maths .!!!!