Question

How many different words can be formed from $12$ consonants and $5$ vowels by taking $4$ consonants and $3$ vowels in each word?

• A. $4950\times 7!$
• B. $7{!}^2$
• C. ${}^{12}{C}_4{\times }^5{C}_3$
• D. none of these

Answer 1

Answer: (A)

$4950\times 7!$

Out of $12$ consonant and $5$ vowels , we have to choose $4$ consonants and $3$ vowels and arrange them among themselves.

Number of words ${=}^{1}2c_4{\times }^5{c}_3\times 7!=4950\times 7!$