We have thirteen letters.
2l,3N,2T,2A and (E,O,L,R)8 (types)
We can select 5(five) letters in the following manner:
1. All different 8C5=8.7.51.2.3=56 ways
2. 2 alike, 3 different 4C1.7C3=435=140 ways (we have 4 sets of alike letters)
3. 3 alike, 2 different 1C1.7C2=1.21=21 ways (we have only one set of 3 alike)
4. 3 alike and 2 alike 1C1.3C1=1.3=3 ways
5.Two sets of alike and one different
4C2.6C1=6.6=36 ways
∴ Total number of selection is
56+140+21+3+36=256 ways ⟹ (d)