Question

How many different words can be formed with the letters of the word NAINITAL such that each of the word begins with L and ends with T?

• A. 90
• B. 80
• C. 88
• D. 82

Answer 1

The correct option is A 90

When L and T are fixed as first and last letters of the word, then we have only 6 letters to be arranged.
Hence required number of permutations $=\frac{6!}{2!\times 2!\times 2!}=90$