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Question

How many distinct positive integers are possible with the digits 1, 3, 5, 7 without repitition ?

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Solution

Possible number of,

single-digit numbers = 4

two-digit numbers = 4×3=12

three-digit numbers = 4×3×2=24

four-digit numbers = 4×3×2×1=24

Thus, total number of distinct positive integers without repitition = 4+12+24+24=64.



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