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Question

How many distinct real roots are possible for the below equation?
x6−26x3−27=0

A
-1, 27
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B
1, -27
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C
-1, 3
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D
1, -3
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Solution

The correct option is B 1, -27

Let x3=y

y226y27=0

y227y+y27=0

y(y27)+1(y27)=0

(y+1)(y27)=0

The roots are y = -1, y = 27

x3=1,x=1

x3=27,x=3


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