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Question

how many elecrons are present in all sub shells fully filled with n+l =6

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Solution

Now the given orbital is n+l = 6So the orbitals present are 6s,5p,4d.l= 0 for : l=1 for p and l=2 for d orbitals orbital can hold maximum of 2 electrons and p orbital hold 6 electrons and d orbitalcan hold maximum of 10 electrons. So6s has 2 electrons - (n + l = 6+0)5p has 6 electrons -(n + l = 5+1)4d has 10 electrons -(n + l = 4+2)

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