wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

how many elecrons are present in all sub shells fully filled with n+l =6

Open in App
Solution

Now the given orbital is n+l = 6So the orbitals present are 6s,5p,4d.l= 0 for : l=1 for p and l=2 for d orbitals orbital can hold maximum of 2 electrons and p orbital hold 6 electrons and d orbitalcan hold maximum of 10 electrons. So6s has 2 electrons - (n + l = 6+0)5p has 6 electrons -(n + l = 5+1)4d has 10 electrons -(n + l = 4+2)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Size of an Atom or Ion
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon