How many electron will constitute 32 C of charge ?

2 \times 10^{19}

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2 \times 10^{18}

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2 \times 10^{17}

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2 \times 10^{20}

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Solution

The correct option is D $2 \times 10^{20}$
The electron will continue $= 32 C$ of charge
electron $= \frac{32}{1.6 \times 10^{- 19}}$
$= \frac{32 \times 10}{16 \times 10^{- 19}}$
$= 2 \times 10^{19 + 1}$
$= 2 \times 10^{20}$
$∵$ each electron has charge $= 1.6 \times 10^{- 19} C$

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How many electron will constitute 32 C of charge ?

The correct option is D 2×1020The electron will continue =32C of chargeelectron =321.6×10−19 =32×1016×10−19 =2×1019+1 =2×1020∵ each electron has charge =1.6×10−19C

The correct option is D $2 \times 10^{20}$
The electron will continue $= 32 C$ of charge
electron $= \frac{32}{1.6 \times 10^{- 19}}$
$= \frac{32 \times 10}{16 \times 10^{- 19}}$
$= 2 \times 10^{19 + 1}$
$= 2 \times 10^{20}$
$∵$ each electron has charge $= 1.6 \times 10^{- 19} C$