How many electrons are possible in all shells with n+1=3

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Solution

$T h e v a r i o u s s u b s e h l l s p r e s e n t a r e n + l = 3 I f n = 3 t h e n l = 0 : n + l = 3 + 0 = 3 . T h e o r b i t a l i s t h e n 3 s . s o b i t a l h o l d 2 e l e c t r o n s . I f n = 2 t h e n l = 1 : n + l = 2 + 1 = 3 . T h e o r b i t a l i s t h e n 2 p . p o r b i t a l c a n h o l d m a x i m u m o f 6 e l e c t r o n s I f n = 1 t h e n l = 2 : n + l = 1 + 2 = 3 . T h e o r b i t a l i s 1 d, w h i c h d o e s n o t e x i s t . S o t h e s u b s h e l l s a r e 3 s a n d 2 p . T h e e l e c t r o n s a r e 2 + 6 = 8 e l e c t r r o n s .$

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