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Question
How many electrons are present in 7g of N³- ion....
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How many electrons are present in 7g of N³- ion....
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Solution
atomic mass of N =14 g
given mass = 7 g
number of moles = 7/14=0.5moles
electrons =10
number of Nitride ions in 1 mole =10*NA
;. number of Nitride ions in 0.5moles = 0.5*10*NA
=5NA
[NA =Avogadro's number
=6.022×10^23]
given mass = 7 g
number of moles = 7/14=0.5moles
electrons =10
number of Nitride ions in 1 mole =10*NA
;. number of Nitride ions in 0.5moles = 0.5*10*NA
=5NA
[NA =Avogadro's number
=6.022×10^23]
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