Question

How many electrons are present in an atom of Silicon?

Answer 1

The number of ${\mathrm{e}}^{-}$ are present in an atom of Silicon $\left(\mathrm{Si}\right)$ are calculated as follows:

Atomic number of Silicon $\left(\mathrm{Si}\right)=14$

Number of ${\mathrm{e}}^{-}$ of neutral atom $=$ Atomic number of neutral atom

Hence, No. of ${\mathrm{e}}^{-}$ in Silicon ($\mathrm{Si}$) atom $=14$

Electronic Configuration $=1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^2$