Question

How many electrons are present in. n+1=5 ?

Answer 1

Dear student..... There are five orbitals which have the same value of (n + l) = 5. These are the 5s, 4p and 3d orbitals. For the 5s orbital, n = 5 and l =0, therefore (n + l) = 5. An s subshell has only one orbital and as an orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5s orbital would be 2. For the 4p orbital, n = 4 and l = 1, therefore (n + l) = 5. As a p subshell has three orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 4p orbital would be 6. For the 3d orbital, n = 3 and l = 2, therefore (n + l) = 5. As a d subshell has five orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5d orbital would be 10. Regards