How many electrons are present in the M shell of an atom of an element with atomic number 24?
Please explain how to find.
If you normally write the electronic configuration of element with atomic number 24, the configuration is
1s2 2s2 2p6 3s2 3p6 4s2 3d4
K shell contains 1s
L shell contains 2s 2p
M shell contains 3s 3p 3d
So the number of electrons if we bluntly follow the configuration is 2+6+4 = 12
24 Cr chromium : [Ar] 3d5 4s11s2 | 2s2 | 2p6 | 3s2 | 3p6 | 3d5 | 4s1 | |||||||||||||||||||
2 | 8 | 13 | 1 |
So the electrons in M shell is 2+6+5 = 13.
It's same as the manganese electronic configuration.