How many electrons can fit in the orbital for which n=3, l=1?

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Solution

Principal quantum number n = 3 - M shell
Azimuthal quantum number is l =1 - P subshell
P subshell has 3 orbitals. each can hold two electrons.
So
Number of orbitals present can be calculated by the formula (2l+1)
Here value of
l=1,
Hence Number of orbitals=2×1+1=3
3p ⟶
↑↓ ↑↓ ↑↓
The p subshell has maximum of 3 orbitals Hence total of 6 electrons can fit for n=3 and l=1

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Similar questions

n = 3

l = 0

How many electrons in an atom may have the following quantum numbers?
(a) n = 4, $m=-\frac{1}{2}$ $\frac{1}{2}$
(b) n = 3, l = 0

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