How many electrons in an atom can have $n = 4, l = 1$ and $m = + 1$ ?

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Solution

The correct option is B $2$
For the Principal quantum number $n = 4$ ,

Azimuthal quantum number $l = 1$

and Magnetic quantum number $m_{l} = + 1$

Two electrons are possible in the given $4 p_{x}$ orbital

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Similar questions

(n + l) = 8

105

(n + 1) = 8

How many electrons in an atom may have the following quantum numbers?
(a) n = 4, $m = - \frac{1}{2}$
(b) n = 3, l = 0

n = 4, m_{s} = - 1 / 2

n = 3, l = 0

n = 3, l = 2, m = + 2, s = + 1 / 2

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