How many electrons in an atom may have the following quantum numbers?(a) n = 4, (b) n = 3, l = 0

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Solution

(a) Total number of electrons in an atom for a value of n = 2n²

∴ For n = 4,

Total number of electrons = 2 (4)²

= 32

The given element has a fully filled orbital as

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰.

Hence, all the electrons are paired.

∴ Number of electrons (having n = 4 and ) = 16

(b) n = 3, l = 0 indicates that the electrons are present in the 3s orbital. Therefore, the number of electrons having n = 3 and l = 0 is 2.

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Similar questions

How many electrons in an atom may have the following quantum numbers?
(a) n = 4, $m=-\frac{1}{2}$ $\frac{1}{2}$
(b) n = 3, l = 0

n = 4, m_{s} = - \frac{1}{2}

n = 3, l = 0

(i) n = 4, m_{s} = - \frac{1}{2}

(i i) n = 3, l = 0

(i i i) n = 2, l = 1

(i v) n = 2, l = 0

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