Question

how many electrons protons and neutrons are present in 207Pb82.write its electronic configuration. how many Valence Electrons does it have ?what will be its valency?

Answer 1

Dear Student,


$$\begin{gathered} \mathrm{For}{{}^{207}}_{82}\mathrm{Pb}, \\ \mathrm{No}.\mathrm{of}\mathrm{electrons}=\mathrm{No}.\mathrm{of}\mathrm{protons}=\mathrm{Atomic}\mathrm{number}=82 \\ \mathrm{Number}\mathrm{of}\mathrm{neutrons}=\mathrm{Mass}\mathrm{number}-\mathrm{Atomic}\mathrm{number} \\ =207-82 \\ =125 \\ \mathrm{Its}\mathrm{electronic}\mathrm{configuration}\mathrm{will}\mathrm{be}\left[\mathrm{Xe}\right]4{\mathrm{f}}^{14}5{\mathrm{d}}^{10}6{\mathrm{s}}^{2}6{\mathrm{p}}^2 \\ \mathrm{Number}\mathrm{of}\mathrm{valence}\mathrm{electrons}=4 \\ \mathrm{Its}\mathrm{valency}\mathrm{is}2. \end{gathered}$$