Question

How many electrons should $X_2{H}_4$ liberate so that in the new compound $X$ shows an oxidation number of $-\frac{1}{2}$?

[E.N.: $X$ $>$ $H$]

• A. $10$
• B. $4$
• C. $3$
• D. $2$

Answer 1

The correct option is C $3$

Let the number of electrons liberated be x then the total charge on compound will be x.

$\therefore 2\times (-\frac{1}{2})+4\times 1=x$

$x=3$

Hence, the correct option is $C$.