How many electrons will be present in the subshells having $m_{s}$ value of $- 1 / 2$ for $n = 4$ ?

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Solution

The correct option is D 16
For n = 4 value of electrons is $2 n^{2}$ = 32
and two electrons is filled in each orbital one have $m_{s}$ value +1/2 and other have -1/2
So for n = 4 there are 16 orbitals and 16 electrons which have $m_{s}$ value is -1/2

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m_{s}

n = 4, m_{s} = - \frac{1}{2}

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