The correct option is C 39
There are 101 integers in all , of which 51 are even.
From 100 to 200 , there are 14 multiples of 7, of which 7 are even.
There are 11 multiples of 9, of which 6 are even.
But , there is one integer 126 that is a multiple of both 7 and 9 and also even.
Hence The answer is (51−7−6+1)=39
Option C is right answer