Question

How many even numbers of 3 different digits can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition is not allowed)

• A. 224
• B. 280
• C. 324
• D. None of these

Answer 1

The correct option is A 224

The number will be even if last digit is 2, 4, 6 or 8 i.e., the last digit can be filled in 4 ways and remaining two digits can be filled in ${}^8{P}_2$ ways. Hence required number of numbers are ${}^8{P}_2\times 4=224$