How many factors of 24000 are odd numbers?

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none of these

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Solution

The correct option is D none of these
Answer=option d

Prime factorize $24000 = 2^{6} \times 3 \times 5^{3}$

Take out $2^{6}$ and then find the number of factors. This will give all the odd factors

In this case, number of factors $= (3 + 1) \times (1 + 1) = 4 \times 2 = 8$

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