Question

How many faradays are released when $12.7g$ of copper metal is changed into copper ions?

Answer 1

Cu $\to$ $C{u}^{2+}$ + 2$e^{-}$

1 mole of Cu release 2 faraday

i.e., 63.5g of Cu release 2 faraday

1g of Cu release farady= $\frac{2}{63.5}$

and 12.7g of Cu release farady = $\frac{2}{63.5}$$\ast 12.7$

number of faraday release= 0.4