Question

How many Faradays are required to generate one gram atom of magnesium from $MgC{l}_2$

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

$2$

one gram atom means one mole.

we have to find the amount of Faraday which is required to generate one mole of magnesium from $MgC{l}_2$.

we know,

$MgC{l}_2\iff M{g}^{2+}+2C{l}^{-}$

$M{g}^{2+}+2e^{-}\iff Mg$

so, it is clear that one mole of magnesium is formed by two moles of electrons.

as $1$ mole of electrons is equivalent to $1$ Faraday of charge

so,$two$ $moles$ of electrons are equivalent to $2$ Faradays of charge.

Therefore $2$ Faradays are required to generate one gram atom of magnesium from $MgC{l}_2$.