How many faradays are required to reduce one mole of $M n O_{4}^{-}$ to $M n^{2 +}$ ?

1

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2

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5

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Solution

The correct option is D $5$
The balanced chemical equation is:
$8 H^{+} + 5 e^{-} + M n O_{4}^{-} \to M n^{2 +} + 4 H_{2} O$

As can be seen from the balanced chemical equation, to reduce one mole of $M n O_{4}^{-}$ $5$ moles of electrons are required.
Hence,
$5 m o l e e^{-} = 5 F a r a d a y$ .

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