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Byju's Answer
Standard VI
Mathematics
Formation of Algebraic Expressions
How many five...
Question
How many five-digit numbers, which do not contain identical digits, can be written by means of the digits
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
and
9
?
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Solution
We have 9 digits and 5 slots to create a 5-digit number.
−
−
−
−
−
↑
First slot has 9 possible choices out of
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
and
9
.so it can be filled in 9 ways.
−
−
−
−
−
↑
Second slot is now,left with 8 choices.so it can be filled in 8 ways.
Similarly,third,fourth and fifth can be filled in 7, 6 and 5 ways respectively.
To get all possible permutations,just multiply these numbers i.e,
9
×
8
×
7
×
6
×
5
=
15120
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