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Question

How many four-digit numbers, each divisible by 4 can be formed using the digits 1, 2, 3, 4 and 5, repetitions of digits being allowed in any number?

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Solution

for no. to be divisible by 'y'
last 'z' digit should be divisible by
'y' 6 only combinations are
12,24,52,32,44,(5ways)
no. of ways of filling 1st 2 Place
are '5' & '5'
total ways are 5×5×5=125

1108126_518549_ans_870d97177a9d498aadc3cbcd889ba42d.jpg

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