Question

How many geometrical isomers and stereoisomers are possible for $\left[Pt\right(N{O}_2\left)\right(N{H}_3\left)\right(N{H}_{2}OH\left)\right(Py){]}^{+}$ and $\left[Pt\right(Br\left)\right(Cl\left)\right(I\left)\right(N{O}_2\left)\right(N{H}_3\left)\right(Py\left)\right]$ respectively?

• A. $3$ and $15$
• B. $3$ and $30$
• C. $4$ and $15$
• D. $4$ and $30$

Answer 1

The correct option is B $3$ and $30$

Three geometrical isomers are possible for the complex $\left[Pt\right(N{O}_2\left)\right(N{H}_3\left)\right(N{H}_{2}OH\left)\right(Py){]}^{+}$ and $15+15=30$ stereoisomers are possible for $\left[Pt\right(Br\left)\right(Cl\left)\right(I\left)\right(N{O}_2\left)\right(N{H}_3\left)\right(Py\left)\right]=15+15$.