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Standard XII
Chemistry
Amino Acids
How many geom...
Question
How many geometrical isomers are possible for the following alkene?
C
H
3
–
C
H
=
C
H
–
C
H
=
C
H
–
C
H
=
C
H
–
C
H
3
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Solution
Total number of geometrical isomers is
2
3
−
1
+
2
3
−
1
2
=
4
+
2
=
6
.
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