How many geometrical isomers are possible in a complex of type [Ma2(AA)2], where a is unidentate and AA is bidentate symmetrical ligand?
A
0
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B
2
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C
3
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D
4
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Solution
The correct option is B 2 In a complex of such type, the two A ligands can be arranged either adjacent to or opposite to each other to form cis and trans isomers respectively, making it a total of two possible isomers.