How many geometrical isomers are possible or $[P d^{2 +} (N H_{2} - C H (C H_{3}) - C O_{2}^{-})_{2}]$ .

2

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3

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4

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6

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Solution

The correct option is C $4$
Total four geometrical isomers are possible for the compound $[P d^{2 +} (N H_{2} - C H (C H_{3}) - C O_{2})_{2}]$ .
Two are cis and two are trans.
Two cis isomers differ in the orientation of the methyl group of the ligand. Also the trans isomers differ in the orientation of the methyl group in the ligand.

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