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Geometrical Isomerism in Square Planar Geometry

How many geom...

Question

How many geometrical isomers are theoretically possible for the formula, $[P t (P y) (N H_{3}) (N O_{2}) C l B r I]$ :

A

3

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B

4

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C

8

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D

15

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Solution

The correct option is D 15
In this complex there are 6 different ligands. It is an [Mabcdef] type of complex. It has 15 geometrical isomers.

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