How many geometrical isomers are there for:
(A) $[C O (N H_{3})_{2} C l_{4}]$ , octahedral?
(B) $[A u C l_{2} B r_{2}]^{-}$ , square planar?
(C) $[C o C l_{2} B r_{2}]^{2 -}$ , tetrahedral?

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Solution

(A) $[C o (N H_{3})_{2} C l_{4}]$ , Octahedral.
(Refer to Image 1)
(B) $[A u C l_{2} B r_{2}]^{-}$ , Square planar.
(Refer to Image 2)
(C) $[C o C l_{2} B r_{2}]$ , Tetrahedral.
The tetrahedral complexes does not form geometrical isomers as all the four ligands are adjacent to one another, they are equidistant from each other.

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